5x+3[x-1]=8[x+2]-10

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Solution for 5x+3[x-1]=8[x+2]-10 equation:


Simplifying
5x + 3[x + -1] = 8[x + 2] + -10

Reorder the terms:
5x + 3[-1 + x] = 8[x + 2] + -10
5x + [-1 * 3 + x * 3] = 8[x + 2] + -10
5x + [-3 + 3x] = 8[x + 2] + -10

Reorder the terms:
-3 + 5x + 3x = 8[x + 2] + -10

Combine like terms: 5x + 3x = 8x
-3 + 8x = 8[x + 2] + -10

Reorder the terms:
-3 + 8x = 8[2 + x] + -10
-3 + 8x = [2 * 8 + x * 8] + -10
-3 + 8x = [16 + 8x] + -10

Reorder the terms:
-3 + 8x = 16 + -10 + 8x

Combine like terms: 16 + -10 = 6
-3 + 8x = 6 + 8x

Add '-8x' to each side of the equation.
-3 + 8x + -8x = 6 + 8x + -8x

Combine like terms: 8x + -8x = 0
-3 + 0 = 6 + 8x + -8x
-3 = 6 + 8x + -8x

Combine like terms: 8x + -8x = 0
-3 = 6 + 0
-3 = 6

Solving
-3 = 6

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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